First slide
Evaluation of definite integrals
Question

01Tan1(2x1x2)dx=

Easy
Solution

01Tan1(2x1x2)dx=012Tan1xdx

              =2[(Tan1x.x)01]20111+x2.xdx

              =2(π40)012x1+x2dx

              =π2(log(1+x2))01

               =π2log2

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