∫tt4+t2−5dt is equal to

∫tt4+t2−5dtt2=z2tdt=dz∫tt22+t2−5dt=∫dzz2+z−5=12∫dzz2+2.z12+122−5−122 Use ∫1x2−a2dx=12alog⁡x−ax+a+c=12∫dzz+122−214=12∫dzz+122−2122=1212212log⁡z+12−212z+12+212+c=1221log⁡2z+1−212z+1+21+c