∫tt4+t2−5dt is equal to
121log2t2+1+212t2+1+21+c
121log2t2−1+212t2+1+21+c
1221log2t2−1+212t2+1+21
1221log2t2+1−212t2+1+21+c
∫tt4+t2−5dt
t2=z
2tdt=dz∫tt22+t2−5dt=∫dzz2+z−5=12∫dzz2+2.z12+122−5−122
Use ∫1x2−a2dx=12alogx−ax+a+c
=12∫dzz+122−214=12∫dzz+122−2122=1212212logz+12−212z+12+212+c=1221log2z+1−212z+1+21+c