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$\int_{0}^{102} [\tan^{- 1} x] d x = Where [.] = G I F$

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Correct option is A

For 0≤x≤tan⁡1 and tan⁡1≤x≤102∫0102 tan−1⁡xdx=∫0tan⁡1 0dx+∫tan⁡1102 1dx=(x)tan1102=102−tan⁡1

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∫0102 tan−1⁡xdx= Where [.]=GIF

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$\int_{0}^{102} [\tan^{- 1} x] d x = Where [.] = G I F$