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Q.

∫0102 tan−1⁡xdx= Where [.]=GIF

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a

102−tan⁡1

b

101

c

102+tan⁡1

d

102−π4

answer is A.

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Detailed Solution

For 0≤x≤tan⁡1 and tan⁡1≤x≤102∫0102 tan−1⁡xdx=∫0tan⁡1 0dx+∫tan⁡1102 1dx=(x)tan1102=102−tan⁡1
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