Correct option is 1tan3x3+tan5x5+C

Questions

$\int \tan^{2} x \sec^{4} x d x$

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tan3x3+tan5x5+C

tan3x3−tan5x5+C

−tan3x3−tan5x5+C

tan6x6+tan4x4+C

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detailed solution

Correct option is A

tan⁡x=t sec2⁡xdx=dt∫t21+t2dt=∫t2+t4dt=t33+t55+C

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∫tan2xsec4x dx

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$\int \tan^{2} x \sec^{4} x d x$