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tanxsin4x+cos4xdx is equal to

 

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a
loge⁡tan2⁡x+1+tan4⁡x+C
b
12loge⁡tan2⁡x+1+tan4⁡x+C
c
14log⁡tan2⁡x+1+tan4⁡x+C
d
none of these

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detailed solution

Correct option is B

LetI=∫tan⁡xsin4⁡x+cos4⁡xdx= l=∫tan⁡xsec2⁡xtan4⁡x+1dx=12∫1tan2⁡x2+1dtan2⁡x⇒ I=12loge⁡tan2⁡x+1+tan4⁡x+C


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