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tanxsinxcosxdx is equal to 

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a
−2tanx+C
b
2tanx+C
c
2cotx+C
d
−2cotx+C

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detailed solution

Correct option is B

Let I=∫tan⁡xsin⁡xcos⁡xdx=∫tan⁡xtan⁡xcos2⁡xdxI=∫sec2xdxtanxdxlet     tanx = tsec2⁡xdx=dtI=∫1tdt=2t+C=2tan⁡x+C


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