∫1+2tanxtanx+secx1/2dx
logsecxsecx−Tanx+C
logSecxSecx+Tanx+C
logSecxTanx−Secx+C
logTanxSecx−Tanx+C
∫1+2tan2x+2tanxsecx1/2dx
=∫sec2x+tan2x+2tancsecx1/2dx=∫sec x+tanxdx=log|secx+tanx|+log|secx|+c=log|secx(secx+tanx)|+c