∫01 tan−11x2−x+1 is equal to
log 2
-log 2
π2+log2
π2-log2
∫01 tan−11x2−x+1dx=∫01 tan−1x−(x−1)1+x(x−1)
=∫01 tan−1xdx−∫01 tan−1(x−1)dx=∫01 tan−1xdx+∫01 tan−1(1−1+x)dx=∫01 tan−1xdx+∫01 tan−1xdx=2∫01 tan−1xdx=2xtan−1x−∫x1+x2dx01=2xtan−1x−12log1+x201=21tan−11−12log(2)−0−12log1=2π4−12log2−0=π2−log2