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a
105−102-1181426
b
105−10211814−2−6
c
105−10211−81426
d
105−1021181426
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Correct option is D
A11=(−1)1+14−212=8+2=10A12=(−1)1+22−2−32=−(4−6)=2A13=(−1)1+324−31=2+12=14A21=(−1)2+1−1312=−(−2−3)=5A22=(−1)2+213−32=2+9=11A23=(−1)2+31−1−31=−(1−3)=2A31=(−1)3+1−134−2=2−12=−10A32=(−1)3+2132−2=−(−2−6)=8A33=(−1)3+31−124=4+2=6 Cofactor matrix of A is B=102145112−1086adj A=BT=105−1021181426Similar Questions
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