∫x2(ax+b)−2dx is equal to
2a2x2−balog(ax+b)+C
2a2x2−balog(ax+b)−b2a3(ax+b)+C
2a2x2+balog(ax+b)+b2a3(ax+b)+C
2a2x2+balog(ax+b)−b2a3(ax+b)+C
I=∫x2(ax+b)2dx
put ax+b=t⇒dx=1adt and x=t−ba
∴ I=1a3∫(t−b)2t2dt=1a3∫1+b2t2−2btdt=1a3t−b2t−2blogt+C
=1a3ax+b−b2ax+b−2blog(ax+b)+C=2a2x2−balog(ax+b)−b2a3(ax+b)+C