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Q.

∫−1 1(ax3+bx) dx=0,∀a,b∈R

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a

any values of a and b

b

a > 0, b > 0 only

c

a > 0, b < 0 only

d

a < 0, b < 0 only

answer is A.

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Detailed Solution

∫−11ax3+bx=0    ∀  a,b∈R ax3+bx  is  odd functions.
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