First slide

Introduction to integration

Question

$\int x C o \sec x C o t x d x =$

Easy

A

$x C o \sec x - \log | \tan \frac{x}{2} | + c$
B

$- x C o \sec x + \log | \tan \frac{x}{2} | + c$
C

$x C o \sec x - 2 \log | \tan \frac{x}{2} | + c$
D

$x C o t x + \log | \tan \frac{x}{2} | + c$

Solution

$\int x (\cos e c x . \cot x) d x$ $= x (- \cos e c x) - \int (- \cos e c x) d x$
$= - x \cos e c x + \log | \tan \frac{x}{2} | + C$

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