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x3dtan1x is equal to 

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a
x22+12ln⁡1+x2+C
b
−x22+12ln⁡1+x2+C
c
−x22−12ln⁡1+x2+C
d
x22−12ln⁡1+x2+C

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detailed solution

Correct option is D

I=∫x3dtan−1⁡x=∫x31+x2dx=∫x−x1+x2dx=x22−12ln⁡1+x2+C


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