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$\int_{0}^{2} |2 x - 1| d x$

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Correct option is C

use definition of absolute value |2x−1|−(2x−1),x<122x−1,x≥12∴∫02 |2x−1|dx=∫01/2 {−(2x−1)}dx+∫i/22 (2x−1)dx=x−x201/2+(x−x)1/22=52

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$\int_{0}^{2} |2 x - 1| d x$