First slide
Evaluation of definite integrals
Question

0aa2x25/2dx=

Moderate
Solution

 Put x=asinθdx=acosθdθ G.I =0π/2a2a2sin2θ5/2(acosθ)dθ=a60π/2cos5θcosθdθ=a60π/2cos6θdθ=a6563412π2=5πa632

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