First slide

Introduction to definite integration

Question

$\int_{- 1}^{2} | x | d x =$

Easy

A

$\frac{5}{2}$
B

$2$
C

$\frac{3}{2}$
D

$1$

Solution

$\int_{- 1}^{2} | x | d x = {[\frac{x | x |}{2}]}_{- 1}^{2}$ $= \frac{4}{2} - (- \frac{1}{2}) = \frac{5}{2}$

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