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Q.

∫−11|2x−1|dx is equal to

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a

−2

b

−1/2

c

1/2

d

5/2

answer is D.

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Detailed Solution

∫−11|2x−1| dx=∫−11/2|2x−1|dx+∫1/21|2x−1|dx =∫−11/2(−(2x−1))dx+∫1/21(2x−1)dx=[x−x2]11/2+[x2−x]1/21=(12−14)−(−1−1)+(1−1)−(14−12)=52

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∫−11|2x−1|dx is equal to