∫03/2[x2]dx, where [] denotes the greatest integer function is
2+2
2−2
4+22
4−22
∫03/2[x2]dx=∫01[x2]dx+∫12[x2]dx+∫23/2[x2]dx
=∫010dx+∫121dx+∫23/22dx
=0+[x]12+[2x]23/2
=2−1+3−22=2−2