∫(x+1)2dxxx2+1 is equal to
logex+c
logex+2tan−1x+c
loge1x2+1+c
logexx2+1+c
∫(x+1)2xx2+1dx=∫x2+1+2xxx2+1dx=∫x2+1xx2+1dx+2∫xxx2+1dx=∫dxx+2∫dxx2+1=logex+2tan−1x+c