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(x+1)2dxxx2+1 is equal to 

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a
loge⁡x+c
b
loge⁡x+2tan−1⁡x+c
c
loge⁡1x2+1+c
d
loge⁡xx2+1+c

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detailed solution

Correct option is B

∫(x+1)2xx2+1dx=∫x2+1+2xxx2+1dx=∫x2+1xx2+1dx+2∫xxx2+1dx=∫dxx+2∫dxx2+1=loge⁡x+2tan−1⁡x+c


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ex1+ex2+exdx is equal to 


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