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ax2dxax+ax is equal to 

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a
logax+ax2+2+C
b
logax+ax2−2+C
c
1logalogax+ax2+1+C
d
1logalogax+ax2−1+C

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detailed solution

Correct option is C

Let I=∫ax2dxax2+1axI=∫ax2ax2dx(ax)2+1=∫axdx(ax)2+1 Put ax=t⇒axdx=1log⁡adtI=∫dtlog a1t2+1=1log⁡alog⁡t+t2+1+C=1log⁡alog⁡ax+ax2+1+C


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