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$\int_{- 2}^{2} | [x] | dx$ is equal to

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Correct option is D

∫−22 |[x]|dx=∫−2−1 |[x]|dx+∫−10 |[x]|dx+∫01 |[x]|dx+∫12 |[x]|dx=∫−2−1 2dx+∫−10 1dx+∫01 0dx+∫12 1dx=2[x]−2−1+[x]−10+0+[x]12=2(−1+2)+(0+1)+(2−1)=2+1+1=4

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∫−22 |[x]|dx is equal to

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$\int_{- 2}^{2} | [x] | dx$ is equal to