∫−23 x2−1dx is equal to

∫−23 x2−1dx=∫−2−1 x2−1dx+∫−11 x2−1dx+∫13 x2−1dx[here, modulus function will change at the points, ,when x2−1=0i. . , at x=±1] so,I=∫−2−1 x2−1dx+∫−11 1−x2dx+∫13 x2−1dx=x33−x−2−1+x−x33−11+x33−x13=23+23+23+23+6+23=283