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$\int_{0}^{4} | x - 1 | dx$ is equal to

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Correct option is D

Let ∫04 |x−1|dxIt can be seen that, (x−1)≤0 when 0≤x≤1 and (x−1)≥0 when 1≤x≤4∴ I=∫01 |x−1|dx+∫14 |x−1|dx=∫01 (1−x)dx+∫ab f(x)dx=∫ac f(x)dx+∫cb f(x)dx=x−x2201+x22−x14=1−12−0+422−4−12−1=12+4+12=5

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∫04 |x−1|dx is equal to

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$\int_{0}^{4} | x - 1 | dx$ is equal to