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$\int_{- 1}^{4} (2 x - 3) dx$ is equal to

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Correct option is D

Let I=∫−14 (2x−3)dx and f(x)=2x−3then,∫f(x)dx=∫(2x−3)dx=2x22−3x=x2−3x=F(x)( say )Now, by the fundamental theorem of integral calculus, we getI=[F(x)]−14=F(4)−F(−1)=(4)2−3(4)−(−1)2−3(−1)=(16−12)−(1+3)=4−4=0

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∫−14 (2x−3)dx is equal to

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$\int_{- 1}^{4} (2 x - 3) dx$ is equal to