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3/210{2x}dx where {.} denotes the fractional part of  x, is equal to

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a
12
b
132
c
232
d
234

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detailed solution

Correct option is D

f(x)={2x} is a periodic function with period  12LetI=∫−3/210 {2x}dx=∫−3(1/2)20(1/2) {2x}dx=23∫01/2 2xdx as {2x}=2x−[2x] and when ∈0,12,[2x]=0=23x201/2=234


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