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An Intiative by Sri Chaitanya
a
5+2+3
b
-5+2-3
c
5-2-3
d
-4+3-2
answer is C.
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Detailed Solution
The function x2 varies as follows between x=(0,2)x2=0 if 0≤x2<1, or 0≤x<11 if 1≤x2<2 or 1≤x<22 if 2≤x2<3 or 2≤x<33 if 3≤x2<4 or 3≤x<2⇒I=∫010.dx+∫121.dx+∫232⋅dx+∫323dx=0+(2−1)+2(3−2)+3(2−3)=2−1+23−22+6−33=5−2−3