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Q.

∫x2ex3cos(ex3)dx=

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a

3sin(ex3)+C

b

sin(ex3)+C

c

13sin(ex3)+C

d

−13sin(ex3)+C

answer is C.

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Detailed Solution

∫x2ex3cos(ex3)dx,  put ex3=t ⇒ex3.3x2=dtdx =13∫3x2ex3cos(ex3)dx=13∫costdt =13(sint)+C.
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