∫xexdx=
2x–ex–4xex
(2x–4x+4)ex
(1–4x)ex
None of these
Putting x=t2, dx=2t dt
I=∫tet.2t dt=2∫t2etdt =2t2.et–4∫tet dt
=2t2.et–4(tet–et) =(2x–4x+4)ex .