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Q.

∫01(x−1)e−xdx=

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a

−1e

b

1e

c

e

d

2e

answer is A.

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Detailed Solution

∫01(x−1)e−xdx =[(x−1)e−x−1]01−∫01e−x−1dx =−(0+1)−(e−x+1)01 =−1−e−1+1=−1e
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∫01(x−1)e−xdx=