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$\int \frac{x e^{x}}{(1 + x)^{2}} d x is equal to$

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exx+1+C

ex(x+1)+C

−ex(x+1)2+C

ex1+x2+C

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detailed solution

Correct option is A

∫exx(x+1)2dx=∫exx+1−1(x+1)2dx=∫ex1x+1+−1(x+1)2dx=ex1x+1+C

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∫xex(1+x)2dx is equal to

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$\int \frac{x e^{x}}{(1 + x)^{2}} d x is equal to$