∫xex(1+x)2dx is equal to
exx+1+C
ex(x+1)+C
−ex(x+1)2+C
ex1+x2+C
∫exx(x+1)2dx=∫exx+1−1(x+1)2dx=∫ex1x+1+−1(x+1)2dx=ex1x+1+C