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Q.

∫xex(1+x)2dx is equal to

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a

exx+1+C

b

ex(x+1)+C

c

−ex(x+1)2+C

d

ex1+x2+C

answer is A.

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Detailed Solution

∫exx(x+1)2dx=∫exx+1−1(x+1)2dx=∫ex1x+1+−1(x+1)2dx=ex1x+1+C

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