First slide
Evaluation of definite integrals
Question

0π/2(xsec2x2+2tanx2)dx=

Easy
Solution

0π/2(xsec2x2+2tanx2)dx= 0π/2ddx(xSec2x2)dx

                                              =(xSec2x2)0π/2

                                             =π2×20=π

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