∫−π/2π/2 x14sin11⁡x+sin2⁡xdx is equal to

The function f(x)=x14sin11⁡x is an odd function,so ∫−π/2π/2 x14sin11⁡xdx=0 Thus the given integral is equal to ∫−π/2π/2 sin2⁡xdx=2∫0π/2 sin2⁡xdx=2⋅12⋅π2=π2