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π/2π/2x14sin11x+sin2xdx is equal to

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0
b
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c
π2
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detailed solution

Correct option is C

The function f(x)=x14sin11⁡x is an odd function,so ∫−π/2π/2 x14sin11⁡xdx=0 Thus the given integral is equal to ∫−π/2π/2 sin2⁡xdx=2∫0π/2 sin2⁡xdx=2⋅12⋅π2=π2


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