∫−π/2π/2 x14sin11x+sin2xdx is equal to
0
π
π2
-π
The function f(x)=x14sin11x is an odd function,
so ∫−π/2π/2 x14sin11xdx=0 Thus the given integral is
equal to ∫−π/2π/2 sin2xdx=2∫0π/2 sin2xdx=2⋅12⋅π2=π2