First slide
Evaluation of definite integrals
Question

π/2π/2x14sin11x+sin2xdx is equal to

Easy
Solution

The function f(x)=x14sin11x is an odd function,

so π/2π/2x14sin11xdx=0 Thus the given integral is 

equal to π/2π/2sin2xdx=20π/2sin2xdx=212π2=π2

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