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Introduction to definite integration
Question
∫
0
π
/
2
x
2
sin
x
d
x
=
Easy
A
π
−
2
B
π
+
2
C
π
+
4
D
π
−
4
Solution
∫
0
π
/
2
x
2
S
i
n
x
d
x
=
[
x
2
(
−
C
o
s
x
)
+
2
x
S
i
n
x
+
2
C
o
s
x
]
0
π
/
2
b
y
p
a
r
t
s
=
π
−
2
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