First slide

Evaluation of definite integrals

Question

$\int_{0}^{π / 2} x \sin x d x =$

Easy

A

0
B

1
C

-1
D

2

Solution

$\int_{0}^{π / 2} x S i n x d x = {(- x C o s x)}_{0}^{π / 2} - \int_{0}^{π / 2} 1. (- S i n x) d x$
$= 0 + {(- C o s x)}_{0}^{π / 2}$

$= 1$

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