∫x sinx sec3x dx =
12[sec2x-tanx]+c
12[xsec2x-tanx]+c
12[xsec2x+tanx]+c
12[sec2x+tanx]+c
∫x sinx sec3x dx=∫x sinx .1cos3x dx =∫x tanx sec2x dx integration by parts, let u=x and v=tanx sec2x =x ∫sec xtanx secx dx−∫sec xtanx secx dxdx =xsec2x2−∫sec2x2dx =xsec2x2−tanx2+c