Download the app

Questions  

x sinx sec3x dx =

Remember concepts with our Masterclasses.

80k Users
60 mins Expert Faculty Ask Questions
a
12[sec2x-tanx]+c
b
12[xsec2x-tanx]+c
c
12[xsec2x+tanx]+c
d
12[sec2x+tanx]+c

Ready to Test Your Skills?

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is B

∫x sinx sec3x dx​=∫x sinx .1cos3x dx​                                  =∫x tanx sec2x dx​                                              integration by parts, let u=x and v=tanx sec2x                                   ​=x ∫sec xtanx secx dx−∫sec xtanx secx dxdx​                                  =xsec2x2−∫sec2x2dx                                  ​=xsec2x2−tanx2+c


Similar Questions

tan1xdx is equal to 


whats app icon
phone icon