∫xsin−1x1−x2dx=
−x−1−x2sin−1x+c
x2−1−x2sin−1x+c
x+1−x2sin−1x+c
x−1−x2sin−1x+c
f(x)=sin−1x⋅g(x)=x1−x2 By using integration by parts
∫xsin−1x1−x2dx= sin-1x-1-x2 -∫11−x2-11−x2 dx =x−1−x2sin−1x+c