∫0πx tanxSecx+Cosxdx=

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

π4

π2

π24

π22

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

I=∫0πx(Tan xSinx+Cos x)dx =π+02∫0πSin x1+Cos2xdx =π22∫0π/2Sinx1+Cos2xdx (∵f(a−x)=f(x)) =π[−Tan−1(Cosx)]0π/2 =−π(0−π4)=π24

Watch 3-min video & get full concept clarity