First slide

Evaluation of definite integrals

Question

$\int_{- 1}^{1} (x - [x]) d x =$

Easy

A

1
B

2
C

0
D

$\frac{1}{2}$

Solution

$x - [x]$ is periodic with period 1
$I = 2 \int_{0}^{1} (x - [x]) d x = 2 \int_{0}^{1} x d x = 1$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App