∫1x1/51+x4/51/2dx, is
1+x4/5+C
521+x4/5+C
x4/51+x4/5+C
none of these
Let I=∫1x1/511+x4/51/2dx
⇒ I=54∫11+x4/51/245x−1/5dx⇒ I=54∫11+x4/51/2d1+x4/5=521+x4/51/2+C