∫−aax+x−2dx=]22,a>2 and [x]denotes the greatest integer , then ∫a−ax+xdx is equal to

∫−a0−2x+2dx+∫02x+2-xdx+∫2a2x−2dx=22-x2+2x-a0+2x02+x2−2x2a=22a2+2a+4+a2−2a−4−4=222a2=18a=3∫−33x+xdx=−3−2−1+1+2                  (x is an odd function)=−3