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$\int \sqrt{\frac{1 - x}{1 + x}} d x$

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sin2x+1−x2+C

cos−1x−1−x2+C

sin−1x−1−x2+C

tan−1+1+x2+C

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detailed solution

Correct option is A

∫1−x1+x1−x1−xdx=∫dx1−x2+∫−xdx1−x2=sin−1⁡x+1−x2+C

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∫1−x1+xdx

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$\int \sqrt{\frac{1 - x}{1 + x}} d x$