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Evaluation of definite integrals
Question
∫
2
5
x
−
2
5
−
x
d
x
=
Easy
A
3
π
4
B
2
π
5
C
3
π
2
D
5
π
2
Solution
∫
2
5
x
−
2
5
−
x
d
x
=
π
2
(
b
−
a
)
=
π
2
(
5
−
2
)
=
3
π
2
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