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x5/21+x7dx is 

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a
27log⁡x7/2+x7+1+c
b
12log⁡x7+1x7−1+c
c
21+x7+c
d
None of these

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detailed solution

Correct option is A

Put x7/2=t∴72x5/2dx=dt∴I=∫27dt1+t2=27log⁡t+1+t2+k=27log⁡x7/2+1+x7+k


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