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Evaluation of definite integrals
Question
∫
−
2
2
(
x
−
|
x
|
)
d
x
=
Easy
A
0
B
2
C
4
D
−
4
Solution
∫
−
2
2
x
−
|
x
|
d
x
=
∫
−
2
0
x
−
|
x
|
d
x
+
∫
0
2
x
−
|
x
|
d
x
=
∫
−
2
0
2
x
d
x
+
∫
0
2
0
d
x
=
(
x
2
)
−
2
0
+
0
=
−
4
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