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(1+x)3xdx =

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a
2x+2x3/2+65x5/2+27x7/2+c
b
2x+2x3/2+65x5/2-27x7/2+c
c
2x-2x3/2+65x5/2+27x7/2+c
d
2x+2x3/2-65x5/2+27x7/2+c

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detailed solution

Correct option is A

∫(1+x)3xdx=∫1+3x+3x2+x3xdx=∫x−12dx+3∫x12dx+3∫x32dx+∫x52dx=x1212+3x3232+3⋅x5252+x7272+c=2x+2x32+65x52+27x72+c


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