∫$$x51+x323dx$$ is equal to

Correct option is 118u8/3−15u5/3+C,u=1+x3

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$\int x^{5} \sqrt[3]{{(1 + x^{3})}^{2}} d x$ is equal to

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18u8/3−15u5/3+C,u=1+x3

38u8/3−35u5/3+C,u=1+x3

−38u8/3+35u5/3+C,u=1+x3

−18u8/3+15u5/3+C,u−1+x3

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detailed solution

Correct option is A

Put 1+x3=t3⇒x2dx=t2dt∫x51+x323dx=∫t3-1t4dt=t88−t55+C=181+x38/3−151+x35/3+C.

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∫x51+x323dx is equal to

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$\int x^{5} \sqrt[3]{{(1 + x^{3})}^{2}} d x$ is equal to