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x4x2+1dx is equal to

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a
x33+x+tan−1⁡x+C
b
x33−x+tan−1+C
c
x22−x+2tan−1⁡x+C
d
x33−x−tan−1⁡x+C

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detailed solution

Correct option is B

Since degree of numerator is greater than the  degree of denominator, we divide them x4x2+1=x2−1+1x2+1so ∫x4x2+1dx=x33−x+tan−1⁡x+C


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