∫x4a6−x6dx is equal to
13sin−1x3a3+C
13sin−1x3a+C
13sin−1x3a6+C
−13sin−1x3a3+C
Let I=∫x4a6−x6dx
I=∫x2a6−x32dx
Put x3=t
x2dx=13dtI=∫13dta32−t2=13sin−1ta3+C=13sin−1x3a3+C