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Q.

∫x3x+1dx is equal to

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a

x+x22+x33−ln⁡|1+x|+C

b

x+x22−x33−ln⁡|1+x|+C

c

x−x22−x33−ln⁡|1+x|+C

d

x−x22+x33−ln⁡|1+x|+C

answer is D.

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Detailed Solution

x3x+1=x3+1−1x+1=−1(x+1)+x2+1−xThus given integral =∫x2+1−x−11+xdx=x33+x−x22−ln⁡|x+1|+C
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∫x3x+1dx is equal to