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x3x+1dx is equal to 

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a
x+x22+x33−ln⁡|1+x|+C
b
x+x22−x33−ln⁡|1+x|+C
c
x−x22−x33−ln⁡|1+x|+C
d
x−x22+x33−ln⁡|1+x|+C

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detailed solution

Correct option is D

x3x+1=x3+1−1x+1=−1(x+1)+x2+1−xThus given integral =∫x2+1−x−11+xdx=x33+x−x22−ln⁡|x+1|+C


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