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$\int \frac{1}{{[(x - 1)^{3} (x + 2)^{5}]}^{1 / 4}} d x is equal to$

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43x−1x+21/4+C

43x+2x-11/4+C

13x−1x+21/4+C

13x+2x-11/4+C

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detailed solution

Correct option is A

l=∫1(x−1)3(x+2)51/4dx =∫1x−1x+23/4(x+2)2dx Let x−1x+2=t⇒3dx(x+2)2=dt⇒ l=13∫1t3/4dt =13t1/41/4+C=43t1/4+C=43x−1x+21/4+C

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∫1(x−1)3(x+2)51/4dx is equal to

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$\int \frac{1}{{[(x - 1)^{3} (x + 2)^{5}]}^{1 / 4}} d x is equal to$